limit h->0 [sqrt((4+h)) - 2]

Evaluate the definite integral.function: (t+8)(t^2+3) with respect to variable t lower limit: -sqrt(2) upper limit: sqrt(2)
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2. asked by Max
3. 653 views
Determine whether on not the following limit exists. If, so compute the limit.lim x->3 of sqrtx - 4 / x^3 +27 sqrt 3 - 4 / x^3 +
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2. asked by Hannah
3. 699 views
Find the limit if it exists.The limit of (sqrt(x+1)-2)/(x-3) as x tends to 3. The limit of (sqrt(x+5)-sqrt(5))/x as x tends to 0
1. 1 answer
2. asked by Anna
3. 487 views
Hello all, I would like some confirmation on a limits question.The limit is as h --> 0, [sqrt [73-5(x+h)] - sqrt (73-5x)]/h I
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2. asked by Tim
3. 491 views
(a) Use a graph off(x) = sqrt(2x^2+9x+5)−sqrt(2x^2+2x+1) to estimate the value of lim x→∞ f(x) to one decimal place.
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2. asked by Kayla
3. 810 views
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
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2. asked by Alexa
3. 3,240 views
N(θ,θ): MLE for a Normal where mean=variance isa) (sqrt(4*bar(X_n^2)+1)-1)/2 and In this problem, we apply the Central Limit
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2. asked by shri
3. 489 views
The following sum[(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2))).(6/n)]+ ... + [(sqrt(36-((6n/n)^2))).(6/n)] is a right
1. 1 answer
2. asked by Salman
3. 879 views
The following sum[(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2))).(6/n)]+ ... + [(sqrt(36-((6n/n)^2))).(6/n)] is a right
1. 0 answers
2. asked by Salman
3. 803 views
The following sum[(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2))).(6/n)]+ ... + [(sqrt(36-((6n/n)^2))).(6/n)] is a right
1. 0 answers
2. asked by Salman
3. 700 views