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integrate:dx/((x-1)sqrt(x^2-2) a tutor here direct
integrate:dx/((x-1)sqrt(x^2-2)
a tutor here direct me to a page but i do not know how to use it i tried but it did not show me
1 answer
asked by
samuel!!!!
389 views
Please do help solve the followings
1) Integrate e^4 dx 2) Integrate dx/sqrt(90^2-4x^2) 3) Integrate (e^x+x)^2(e^x+1) dx 4)
0 answers
asked by
Febby-1
1,270 views
Integrate: 1/(x-sqrt(x+2) dx
I came up with: (2/3)(2*ln((sqrt(x+2))-2)+ln((sqrt(x+2))-1)) but it keeps coming back the wrong
0 answers
asked by
COFFEE
579 views
Calc length of arc of y=ln(x) from x=1 to x=2
---- So far: Definite Integral over x=(1,2) of sqrt(1 + 1/x) dx 1/x = tan^2 t x =
1 answer
asked by
mathstudent
668 views
Question: ∫(x^2)/sqrt(x^2+1)
u=x^2+1 , x^2= u-1, du=2xdx ∫(u-1)/sqrt(u) , expand ∫u/sqrt(u) - 1/sqrt(u) Integrate:
1 answer
asked by
Liam
598 views
Integrate: dx/sqrt(x^2-9)
Answer: ln(x + sqrt(x^2 - 9)) + C I'm getting the wrong answer. Where am I going wrong: Substitute: x =
6 answers
asked by
mathstudent
860 views
integrate:cos^10xdx
even with the previous hint a tutor here gave me i still don,t know it
3 answers
asked by
newton
696 views
Please can anyone help with the following problems - thanks.
1) Integrate X^4 e^x dx 2) Integrate Cos^5(x) dx 3) Integrate
0 answers
asked by
Febby
835 views
Find arc length of y=logx from x=1 to x=2.
dy/dx)^2=1/x^2 arc length=Int of [sqrt(1+1/x^2)]dx =Int of [sqrt(1+x^2)/x^2] =Int of
3 answers
asked by
MS
479 views
Find arc length of y=logx from x=1 to x=2.
dy/dx)^2=1/x^2 arc length=Int of [sqrt(1+1/x^2)]dx =Int of [sqrt(1+x^2)/x^2] =Int of
0 answers
asked by
MS
945 views