im stuck on factoring (x-1)(2x^3+13x^2+8x-35)

I am doing the Factoring Quadratic Expressions Quiz, has anyone done it? I am really stuck on it.
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2. asked by Jessica
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im stuck on factoring (x-1)(2x^3+13x^2+8x-35)do i use synthetic division? if so what zero? thnks.
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2. asked by Rebekah
3. 592 views
im stuck on factoring (x-1)(2x^3+13x^2+8x-35)do i use synthetic division? if so what zero? thnks.
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2. asked by Rebekah
3. 453 views
solve by factoring (i know they are are divisible by 14, but I'm stuck) Thank you210x^3 + 266x^2 + 14x - 42 = 0
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2. asked by ARIANA
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Factor the polynomialX^3 + 7x^2 +15x + 9 I tried factoring by grouping. I got stuck at this part: x^2 ( x + 7 )...
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2. asked by Tea
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Determine the zeros of each function by factoring:a. f(x)=-2x^2-5x+12 b. f(x)=2x^2-3x-2 c. f(x)=x^2-10x+24 I have been trying to
1. 1 answer
2. asked by Rhys
3. 565 views
I need to factoring to simpliest form.i am stuck on these last six problems. 2a² + a²b + ab + 1 12m²p + 35nq³ (a-2)²-1
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2. asked by Norma
3. 667 views
I'm stuck on this one:factoring polynomials from algebraic expressions (and it says you can use the substitution method):
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2. asked by dan
3. 590 views
i am doing factoring with quadratic trinomials, And I don't understand any of it!The problem im working on is 5p2-22p+8 I
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2. asked by Tiffany
3. 498 views
Find the solutions for sec^2x+secx=2 that fit into the interval [0, 2pi]I figured out that pi/3 (after factoring and switching
1. 2 answers
2. asked by Sharon
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