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how do you do sinAcosA=cosA-cos^3A/sinA
Hello I am having trouble with proving this:
sinA/secA+secA/cscA = tan(A)(2-sin^2(A)) So far I've gotten SinA/(1/cosA) +
1 answer
asked by
Jimbo
800 views
Hi, can someone give me the answer to this question:
secA-tanA=1/4. Find cosA I got: CosA=4(1-sinA) Is my answer good? Now
2 answers
asked by
Shym
926 views
how do you do sinAcosA=cosA-cos^3A/sinA
2 answers
asked by
PLEASE HELP!!!
921 views
Verify/prove that:
sinAcosA/1-cosA = sin^2/tanA-sinA
1 answer
asked by
Kid
657 views
Prove that [sinA/(1-cosA)-(1-cosA)/sinA]*[cosA/(1+sinA)+(1+sinA)/cosA]=4cosecA
I the second part as 2 secA
1 answer
asked by
Agastya
733 views
Let P=(cosA sinA)
(sinA cosA) Q=(cosB sinA) (sinB cosA) show that PQ=(cosA(A-B) sin(A B)) (sinA(A B) cos(A-B))
0 answers
asked by
James
716 views
1. (sec^2x-6tanx+7/sec^2x-5)=(tanx-4/tanx+2)
2. (sin^3A+cos^3A/sinA+cosA)=1-sinAcosA 3. csc^6x-cot^6x+1+3csc^2xcot^2x please help
1 answer
asked by
George
763 views
Given that sinA=2/5 and that A is obtuse,find the value of cosA.
👍 0 👎 0 👁 25 asked by Raj yesterday at 4:18am sinA =
1 answer
asked by
Raj
1,208 views
CosA/1+sinA=1-sinA/cosA
I have to prove the identity each side has to b the same how would i do that? I have a unit test on
5 answers
asked by
Kristien
621 views
I need to count this:
a) 1-tg^2a/1+ctg^2a, when sina =2/3 b) 1-tg^2a/1-ctg^2a, when cosa= -1/3 c) tga * cos^2a, when sina +
1 answer
asked by
Evelina
613 views