for sin2x+cosx=0, use double-angle or

Use the double angle identities to find sin2x if sinx= 1/square of 17 and cosx<0 . Give exact answer.
1. 3 answers
2. asked by conner
3. 1,356 views
for sin2x+cosx=0, use double-angle or half-angle formula to simplify the equation and then find all solutions of the equation in
1. 2 answers
2. asked by bob
3. 842 views
IF X IS AN ANGLE IN THE FIRST QUADRANT AND COSX= 3/5, FIND THE EXACT VALUE OF SIN2XDONT UNDERSTAND, KNOW THAT THE COSX IS ON A
1. 1 answer
2. asked by KODA
3. 501 views
sin2x+cosx=0 , [-180,180)= 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^-1(0) x1=90 x2=360-90 x2=270 270 doesn't fit in
1. 1 answer
2. asked by Anonymous
3. 895 views
hey, i would really appreciate some help solving for x when:sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
1. 0 answers
2. asked by elle
3. 693 views
the double angle identity for sin2x is sin2x=
1. 1 answer
2. 33 views
Solve:cos(2x-180) - sin(x-90)=0 my work: cos2xcos180 + sin2xsin180= sinxcos90 - sin90cosx -cos2x - sin2x= cosx -cos^2x + sin^2x
1. 0 answers
2. asked by Jess
3. 755 views
Really Stumped on this one, any help would be great! Thanks!Find the exact value of cos 2x using the double angle formula.
1. 1 answer
2. asked by Daemon
3. 423 views
Verify the identity.sin2x/cosx + sinx = 2sinx Solve for all values of x: 6cos2x-7cosx-3=0 If f(x)=cos1/2x-sin2x find the value
1. 1 answer
2. asked by .
3. 850 views
solve algebreically the equationcos2x=1-sinx also cosx=cosx-1 and please also sin2x=3sinx
1. 1 answer
2. asked by adil ahmed
3. 631 views