find sin2x, cos2x, and tan2x

find all solutions in interval [0,2pi]tan²x = -3/2 secx This question may look tricky, but its actually quite simple. First:
1. 0 answers
2. asked by ethan
3. 728 views
tanx= -12/5 x in Q 2.find sin2x= cos2x= tan2x=
1. 1 answer
2. asked by Sam
3. 686 views
secx = 4 in Q2 find sin2x,cos2x,tan2x
1. 2 answers
2. asked by j
3. 852 views
Verify the trigonometric identity:[(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I can't figure this out.
1. 0 answers
2. asked by Matt
3. 664 views
Verify the trigonometric identity:[(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I still can't figure this out.
1. 2 answers
2. asked by Matt
3. 1,316 views
tanx= -12/5 x in quadrant 2find; sin2x= cos2x= tan2x=
1. 1 answer
2. asked by Adam
3. 1,556 views
sin2x − cos2x − tan2x = 2sin2x − 2sin4x − 1/1 − sin2x for x = 45
1. 1 answer
2. asked by thomas
3. 567 views
find sin2x, cos2x, and tan2x if sinx= -1/sqrt 5 and x terminates in quadrant II
1. 1 answer
2. asked by moch
3. 667 views
find sin2x, cos2x, and tan2x if sinx= -2/sqrt 5 and x terminates in quadrant III
1. 1 answer
2. asked by Elena
3. 5,250 views
Find sin2x, cos2x, and tan2x if cosx=−2/sqrt 5 and x terminates in quadrant II.
1. 1 answer
2. asked by Tristan
3. 186 views