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factor 2x^4+12x^3-18x^2-108x
factor 6x^4 +66x^3 +108x^2
1 answer
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factor 2x^4+12x^3-18x^2-108x
1 answer
asked by
B
572 views
how do i factor
27x^3-21x^2y+108x^2-84yx
1 answer
asked by
miguel
527 views
what would be the obleque asymptote to f(x)=(x^7-9x^6+19x^5+23x^4-108x^3+82x^2+64x-120)/(x+3)
0 answers
asked by
sam
405 views
(90x^22y^17−108x^17y^11+90x^16y^4)/−9x^5y^2
my answer is : -(2x^11y^2)(5x^6y^13-6xy^7+5) but it says it can be simplified
1 answer
asked by
mathhelper
548 views
I please need help in solving a cube surface 6x^2+108x+486
2 answers
asked by
BERNIE
498 views
using long division what is x^(7)-9x^(6)+19x^(5)+23x^(4)-108x^(3)+82x^2)+64x-120 divided by (x+3)
1 answer
asked by
sam
498 views
Rewrite 3y^2 + 6y + 108x - 969=0 in standard form, show work.
1 answer
asked by
95
408 views
Parabola:
Rewrite 3y^2 + 6y + 108x - 969=0 in standard form, show work.
2 answers
asked by
95
510 views
Deermine the derivative of f(x)=[(3x^2+1)^3+1]^2. Express your answer in simplified form.
For this I got
1 answer
asked by
Kim
631 views