determine the solutions for tanxcos^2x-tanx=0

  1. Determine solutions for:tanxcos^2x - tanx = 0 in the interval[-2pi, 2pi]
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    2. o asked by o
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  2. determine the solutions for tanxcos^2x-tanx=0 in the interval XE[-2pi,2pi]Ok, please describe the steps to me that you used to
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    2. Anonymous asked by Anonymous
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  3. For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows;
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    2. CodyJinks asked by CodyJinks
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  4. Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
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    2. Marrion asked by Marrion
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  5. Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
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    2. Marrion asked by Marrion
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  6. 2tan^2x-tanx-1=00<x<2pi •MATH - Steve, Thursday, July 18, 2013 at 11:48am (2tanx+1)(tanx-1) = 0 tanx = -1/2 or 1 ... Recall in
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    2. ROBIN asked by ROBIN
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  7. Perform the addition or subtraction.tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the
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    2. Hannah asked by Hannah
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  8. How do I solve this?tan^2x= 2tanxsinx My work so far: tan^2x - 2tanxsinx=0 tanx(tanx - 2sinx)=0 Then the solutions are: TanX=0
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    2. Chris asked by Chris
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  9. Derivative of y=sec(tanx)?I don't get how it is secxsecx*secxtanx*tanxtanx. Where does an extra tanx come from? Derivative of
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    2. Beth asked by Beth
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  10. Did I do this problem right?Find the first and second derative-simplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'=
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    2. Janet asked by Janet
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