determine the solutions for tanxcos^2x-tanx=0

Determine solutions for:tanxcos^2x - tanx = 0 in the interval[-2pi, 2pi]
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2. asked by o
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determine the solutions for tanxcos^2x-tanx=0 in the interval XE[-2pi,2pi]Ok, please describe the steps to me that you used to
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2. asked by Anonymous
3. 2,660 views
For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows;
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2. asked by CodyJinks
3. 824 views
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
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2. asked by Marrion
3. 748 views
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
1. 1 answer
2. asked by Marrion
3. 746 views
2tan^2x-tanx-1=00<x<2pi •MATH - Steve, Thursday, July 18, 2013 at 11:48am (2tanx+1)(tanx-1) = 0 tanx = -1/2 or 1 ... Recall in
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2. asked by ROBIN
3. 651 views
Perform the addition or subtraction.tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the
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2. asked by Hannah
3. 830 views
How do I solve this?tan^2x= 2tanxsinx My work so far: tan^2x - 2tanxsinx=0 tanx(tanx - 2sinx)=0 Then the solutions are: TanX=0
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2. asked by Chris
3. 3,863 views
Derivative of y=sec(tanx)?I don't get how it is secxsecx*secxtanx*tanxtanx. Where does an extra tanx come from? Derivative of
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2. asked by Beth
3. 812 views
Did I do this problem right?Find the first and second derative-simplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'=
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2. asked by Janet
3. 735 views