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determine the solutions for tanxcos^2x-tanx=0
Determine solutions for:
tanxcos^2x - tanx = 0 in the interval[-2pi, 2pi]
1 answer
asked by
o
590 views
determine the solutions for tanxcos^2x-tanx=0 in the interval XE[-2pi,2pi]
Ok, please describe the steps to me that you used to
1 answer
asked by
Anonymous
2,618 views
For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows;
5 answers
asked by
CodyJinks
768 views
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.
I don't know what i'm supposed to
0 answers
asked by
Marrion
687 views
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.
I don't know what i'm supposed to
1 answer
asked by
Marrion
680 views
2tan^2x-tanx-1=0
0<x<2pi •MATH - Steve, Thursday, July 18, 2013 at 11:48am (2tanx+1)(tanx-1) = 0 tanx = -1/2 or 1 ... Recall in
5 answers
asked by
ROBIN
600 views
Perform the addition or subtraction.
tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the
1 answer
asked by
Hannah
772 views
How do I solve this?
tan^2x= 2tanxsinx My work so far: tan^2x - 2tanxsinx=0 tanx(tanx - 2sinx)=0 Then the solutions are: TanX=0
1 answer
asked by
Chris
3,785 views
Derivative of y=sec(tanx)?
I don't get how it is secxsecx*secxtanx*tanxtanx. Where does an extra tanx come from? Derivative of
1 answer
asked by
Beth
751 views
Did I do this problem right?
Find the first and second derative-simplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'=
1 answer
asked by
Janet
671 views