dTdz=−α forz≤11 km where α=6.5

dTdz=−α forz≤11 kmwhere α=6.5 K/km (Kelvin per km) and z is the height above the sea level. The temperature stays then
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2. asked by Anonymous
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To a good approximation, the temperature T drops almost linearly with altitude up to 11 km above sea level, at a constant rate:d
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2. asked by Angelina
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What is the solution of the equation 10(x-1)=50 when solving forz
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2. asked by Cat
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Find the missing value forz?z6=z18\frac{z^?}{z^{6}}=z^{18}z6z?=z18
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dT/dz=−α forz≤11 kmwhere α=6.5 K/km (Kelvin per km) and z is the height above the sea level. The temperature stays then
1. 7 answers
2. asked by Anonymous
3. 814 views
dT/dz=−α forz≤11 kmwhere α=6.5 K/km (Kelvin per km) and z is the height above the sea level. The temperature stays then
1. 5 answers
2. asked by Anonymous
3. 797 views
dT/dz=−α forz≤11 kmwhere α=6.5 K/km (Kelvin per km) and z is the height above the sea level. The temperature stays then
1. 1 answer
2. asked by Anonymous
3. 672 views