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cosx+sinx/cosx-sinx = sec2x+tan2x

  1. PLEASEE HELPPMEEE!!!!cot2x+sec2x=tan2x+csc2x and 1+2sinxcosx/sinx+cosx=sinx + cosx
    1. answers icon 1 answer
    2. Sabrina asked by Sabrina
    3. views icon 750 views
  2. How would you solve the trigonometric identity (cosx-sinx)/(cosx+sinx)=sec2x-tan2x?
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    2. Riley asked by Riley
    3. views icon 480 views
  3. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 1,072 views
  4. Prove:tan2x+sec2x = cosx+sinx/ cosx-sinx
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    2. Beatriz asked by Beatriz
    3. views icon 4,888 views
  5. prove that(cosx - sinx) / (cosx + sinx) = sec2x - tan2x
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    2. urgent asked by urgent
    3. views icon 360 views
  6. tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
    1. answers icon 0 answers
    2. shan asked by shan
    3. views icon 978 views
  7. cosx+sinx/cosx-sinx = sec2x+tan2x
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    2. Anon asked by Anon
    3. views icon 177 views
  8. I need to prove that the following is true. Thanks(cosx / 1-sinx ) = ( 1+sinx / cosx ) I recall this question causing all kinds
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    2. abdo asked by abdo
    3. views icon 994 views
  9. prove the identity(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
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    2. JungJung asked by JungJung
    3. views icon 912 views
  10. If y=3/(sinx+cosx) , find dy/dxA. 3sinx-3cosx B. 3/(sinx+cosx)^2 C. -3/(sinx+cosx)^2 D. 3(cosx-sinx)/(sinx+cosx)^2 E.
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 664 views