cosA= 5/9 find cos1/2A are

y = 2[cos1/2(f1 - f2)x][cos1/2(f1 + f2)x]let f1 = 16 let f2 = 12 therefore y = 2[cos1/2(16 - 12)x][cos1/2(16 + 12)x] y =
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2. asked by Lola
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I need to prove that the following is true. Thanks.csc^2(A/2)=2secA/secA-1 Right Side=(2/cosA)/(1/cosA - 1) =
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2. asked by Dirk
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cosA= 5/9 find cos1/2Aare you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
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2. asked by Anonymous
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If S=1/2^2cos1 + 1/cos1¤cos2+1/2^3 cos1 ¤cos2¤cos2^2 + .......... upto 10 terms . If S= sina(cotb-cotc) where a,b,c€N Then
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2. asked by piyush yadav
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If the radius of a circle is 3960the angle is 1.59 the arc length is 110 how would I find the hypotenuse? I think it is
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2. asked by Amy~
3. 496 views
Hi, can someone give me the answer to this question:secA-tanA=1/4. Find cosA I got: CosA=4(1-sinA) Is my answer good? Now
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2. asked by Shym
3. 926 views
Given that sinA=2/5 and that A is obtuse,find the value of cosA.👍 0 👎 0 👁 25 asked by Raj yesterday at 4:18am sinA =
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2. asked by Raj
3. 1,208 views
Prove that [sinA/(1-cosA)-(1-cosA)/sinA]*[cosA/(1+sinA)+(1+sinA)/cosA]=4cosecAI the second part as 2 secA
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2. asked by Agastya
3. 733 views
If A is between 270degrees and 360degrees, and cos A=12/13, find the exact value of:sin2a, cos2a, sin1/2a, cos1/2a
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2. asked by Bob
3. 1,167 views
Let P=(cosA sinA)(sinA cosA) Q=(cosB sinA) (sinB cosA) show that PQ=(cosA(A-B) sin(A B)) (sinA(A B) cos(A-B))
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2. asked by James
3. 717 views