Ask a New Question
cos6x+2cos^x=1
cos6x+2cos^x=1
1 answer
asked by
Hakim
398 views
cosA= 5/9 find cos1/2A
are you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
0 answers
asked by
Anonymous
872 views
write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x),
1 answer
asked by
kate
557 views
write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x),
0 answers
asked by
jake
976 views
write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x),
0 answers
asked by
Kalen
604 views
What am I doing wrong?
Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
1 answer
asked by
Anonymous
1,050 views
Determine the solution of the equetion: 2cos x-1=0? 2cos x=0? and 2cos x+1=0?
3 answers
asked by
Miley
551 views
how does 2cos(2x)-2cos(x)sin(x) becomes 2cos(2x)-sin(2x)? Try to explain each step simply.
1 answer
114 views
Identify the equation for the following graph: (1 point) Responses y=2cos(2x) y is equal to 2 cosine 2 x y=−2cos(2x) y is
1 answer
126 views
Multiply then use fundamental identities to simplify the expression below and determine which of the following is not equivalent
1 answer
asked by
Tristian
1,722 views