Ask a New Question
Menu

cos2x-sinx=0. Factor and solve for

  1. Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
    1. answers icon 1 answer
    2. Maggie asked by Maggie
    3. views icon 873 views
  2. Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
    1. answers icon 4 answers
    2. Brian asked by Brian
    3. views icon 821 views
  3. cos2x-sinx=0. Factor and solve for sinx
    1. answers icon 5 answers
    2. anon asked by anon
    3. views icon 677 views
  4. the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
    1. answers icon 3 answers
    2. alex asked by alex
    3. views icon 887 views
  5. Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve
    1. answers icon 5 answers
    2. Anonymous asked by Anonymous
    3. views icon 869 views
  6. solve for (<_ = less than or equal to / pie = pie sign / -pie = negative pie)3 sin²x = cos²x ; 0 <_ x < 2pie cos²x - sin²x =
    1. answers icon 3 answers
    2. Julie asked by Julie
    3. views icon 1,096 views
  7. solve each equation for 0=/<x=/<2pisin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx - 3)(sinx
    1. answers icon 7 answers
    2. sh asked by sh
    3. views icon 980 views
  8. solve Sinx=Cos2x-1 for 0¡Üx<2¦Ð
    1. answers icon 0 answers
    2. dfg asked by dfg
    3. views icon 474 views
  9. solve for sinx=cos2x (between 0 and 2pi)
    1. answers icon 2 answers
    2. rachel asked by rachel
    3. views icon 464 views
  10. Solve Sinx=Cos2x-1 for all values between 0 and 2pi
    1. answers icon 1 answer
    2. dfg asked by dfg
    3. views icon 552 views