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cos2x-cosx+1=0 solve this

  1. Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
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    2. Brian asked by Brian
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  2. Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve
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    2. Anonymous asked by Anonymous
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  3. Solve:cos(2x-180) - sin(x-90)=0 my work: cos2xcos180 + sin2xsin180= sinxcos90 - sin90cosx -cos2x - sin2x= cosx -cos^2x + sin^2x
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    2. Jess asked by Jess
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  4. solve algebreically the equationcos2x=1-sinx also cosx=cosx-1 and please also sin2x=3sinx
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    2. adil ahmed asked by adil ahmed
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  5. Solve for x in the interval 0<=x<360:1. 2sin2x+cosx =0 2. cos2x=-2sinx 3. tanx=2sinx 4. 3cos2x+cosx+2=0
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    2. ` asked by `
    3. views icon 648 views
  6. q1) 2cos2x is f(x)-square root3 is g(x) solve f(x)-g(x)=0 to get points of intersection in x is between 0 and 180degrees q2) a)
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    2. MR MATHEW MATICS asked by MR MATHEW MATICS
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  7. Having trouble with this problem:Rewrite the expression as an equivalent expression that does not contain powers greater than 1.
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    2. Brian asked by Brian
    3. views icon 1,444 views
  8. cos2x-cosx+1=0solve this
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    2. adil asked by adil
    3. views icon 578 views
  9. Prove that cos3x/cosx-cos6x/cos2x=2(cos2x-cos4x)
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    2. Joel asked by Joel
    3. views icon 1,170 views
  10. Where do I start to prove this identity:sinx/cosx= 1-cos2x/sin2x please help!! Hint: Fractions are evil. Get rid of them. Well,
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    2. maria asked by maria
    3. views icon 825 views