cos2x=cosx in interval of [0,2pie]

cos2x=cosx in interval of [0,2pie]
1. 2 answers
2. asked by caitlyn
3. 597 views
find all solutions to the equation in the interval [0,2pie]cos2x=cosx
1. 2 answers
2. asked by emily
3. 551 views
Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve
1. 5 answers
2. asked by Anonymous
3. 856 views
Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
1. 4 answers
2. asked by Brian
3. 807 views
Could someone help me with those two questions. I need to know how to do them without calculatorsolve for the interval [0,2pie]
1. 1 answer
2. asked by Anonymous
3. 503 views
Find solutions on interval 0,2pie(cosx/1+sinx) + (1+sinx/cosx) = -4
1. 3 answers
2. asked by Chets
3. 537 views
Solve for x in the interval 0<=x<360:1. 2sin2x+cosx =0 2. cos2x=-2sinx 3. tanx=2sinx 4. 3cos2x+cosx+2=0
1. 0 answers
2. asked by `
3. 663 views
Find all solutions to the equation in the interval [0,2pi)Cosx-cos2x
1. 2 answers
2. asked by Abbey
3. 848 views
Solve:cos(2x-180) - sin(x-90)=0 my work: cos2xcos180 + sin2xsin180= sinxcos90 - sin90cosx -cos2x - sin2x= cosx -cos^2x + sin^2x
1. 0 answers
2. asked by Jess
3. 784 views
solve for (<_ = less than or equal to / pie = pie sign / -pie = negative pie)3 sin²x = cos²x ; 0 <_ x < 2pie cos²x - sin²x =
1. 3 answers
2. asked by Julie
3. 1,085 views