cos²(θ) – 3sin(θ) – sin²(θ)=

cos²(θ) – 3sin(θ) – sin²(θ)= –2____________________________ I am having a hard time figuring out what to do. Do I use
1. 2 answers
2. asked by sweetiepie
3. 525 views
a. Given that sin2 𝑥, cos2 𝑥 𝑎𝑛𝑑 5cos2𝑥 − 3sin2 𝑥 are in arithmetic progression, find the value ofi.
1. 3 answers
2. asked by Benny
3. 157 views
prove that: sin²(3x) + cos²(3x) + sin²(x) - cos²(x) = 0
1. 5 answers
2. asked by yang
3. 1,287 views
Solve the following trigonometry identities.a) 1-cos2(theta) = sin(theta)cos(theta)/cot(theta) b)
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2. asked by Zoë
3. 721 views
The expression 4 - cos² A is equivalent to1)5 - sec² A 2)5 - sin² A 3)5 + sin² A 4)5/sec² A
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2. asked by Moe
3. 668 views
8 sin²(3x) cos²(3x) = 2 [2 sin(3x) cos(3x)]²= 2 [sin(6x)]² = 2[1 - cos(12x)]/2 = 1 - cos(12x)
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2. asked by Carry
3. 1,026 views
ʃ sin² cos² dx
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2. asked by zainab
3. 504 views
tan² θ cos² θ – sin² θ
1. 3 answers
2. asked by chants
3. 198 views
verify the identity.cos2 x - sin2 x = 1 - 2sin2 x the 2's next to the sin and cos on the right sides are powers.
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2. asked by alaina
3. 506 views
Can you explain this to me please?sin2 A + cos2 A = 1 ... (1) 1 + tan2 A = sec2 A ... (2) 1+ cot2 A = cosec2 A ... (3)
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2. asked by Anonymous
3. 461 views