cos^6A-sin^6A=cos2A(1-1÷4sin^2 2A) Prove

cos^6A-sin^6A=cos2A(1-1÷4sin^2 2A) Prove
1. 2 answers
2. asked by kishor
3. 2,882 views
how do you solve this.prove: cos2A plus cosA divided by sin2A minus sinA equal to cos2A plus 1 divided by sinA
1. 1 answer
2. asked by lungisile ntobela
3. 1,184 views
Solve the equation for solutions in the interval 0<=theta<2piProblem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1
1. 2 answers
2. asked by Renee
3. 1,756 views
Prove:1/cos2A+sin2A/cos2A=sinA+cosA/cosA-sinA
1. 1 answer
2. asked by Piwo
3. 1,226 views
Prove:1/cos2A+sin2A/cos2A=sinA+cosA/cosA-sinA
1. 1 answer
2. asked by Piwo
3. 638 views
Prove thatsin(n+1)Asin(n-1)A + cos(n+1)Acos(n-1)A = cos2A
1. 1 answer
2. asked by Kewal
3. 1,212 views
If A + B + C = 180°, Prove thatCos²A + Cos²B - Cos²C = 1 – 2sinAsinBcosC
1. 1 answer
2. asked by Kewal
3. 696 views
if A+B+C=180degrees, prove that 2sin(B+C)sinA=1-cos2A
1. 3 answers
2. asked by Sarah
3. 583 views
If A + B + C = 180° prove thatcos2A + cos2B – cos2C = -1 -4cosAcosBcosC
1. 0 answers
2. asked by Kewal
3. 499 views
If A + B + C = 180°, Prove thatCos²A + Cos²B + Cos²C = 1-2cosAcosBcosC
1. 2 answers
2. asked by Kewal
3. 10,741 views