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cos@-4SIN@=1 then sin@+4cos@=
Solve the equation for solutions in the interval 0<=theta<2pi
Problem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1
2 answers
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Renee
1,756 views
Which equation would the table of values represent? 0, 3 pi over 2, 3 pi, 9 pi over 2, 6 pi. 0, 4, 0, -4, 0 (1 point) Responses
1 answer
108 views
Write an equation for simple harmonic motion, given that the amplitude equals 4 inches and the period equals 2 seconds and the
1 answer
asked by
Kayla
563 views
cos@-4SIN@=1 then sin@+4cos@=
1 answer
asked by
bhavya
547 views
(3-4sin^2a)(1-3tan^2a)=(3-tan^2a)(4cos^2a-3)
1 answer
asked by
Optional
925 views
(3-4sin^2A)(1-3tan^2A) =(3-tan^2A)(4cos^A-3)
0 answers
asked by
Shreya
786 views
(3-4sin^2thita)(1-3tan^A)=(3-tan^2A)(4cos^2A-3)
4 answers
asked by
Soniya
394 views
Find the area under y=4sin(x) and above y=4cos(x) for π2≤x≤3π2.
1 answer
asked by
Destiny Padgett
152 views
Prove that:(3-4sin^2A) (1-3tan^2A)=(3-tan^2A)(4cos^2A-3)
1 answer
asked by
Rishabh
1,488 views
solve the equation
1+4sin(x)=4cos^2(x)
2 answers
asked by
bandit5571
466 views