cos(t)/(5sin(t)+8)^2 the answer i got

  1. the question asks to integrate cos(t)/ (5sin(t)+8)^2 the answer i got was xcos(t)/(5sin(t)+8)^2 this is not right i believe
    1. answers icon 1 answer
    2. sonia asked by sonia
    3. views icon 491 views
  2. cos(t)/(5sin(t)+8)^2the answer i got was: xcos(t)/(5sin(t)+8)^2 this is not right when i put it in what did i do wrong?
    1. answers icon 5 answers
    2. sonia asked by sonia
    3. views icon 537 views
  3. the question asks to integrate cos(t)/(5sin(t)+8)^2 the answer i got wasxcos(t)/(5sin(t)+8)^2 i think the x is wrong but i am
    1. answers icon 0 answers
    2. sonia asked by sonia
    3. views icon 569 views
  4. antiderivativef''=3x+5sin(x) f(0)=4 f'(0)=4 Find f(x) I got (1/2)x^3-5sin(x)+(15/2)x+(7/2), but it was wrong
    1. answers icon 0 answers
    2. Anonymous asked by Anonymous
    3. views icon 508 views
  5. Find the length of the entire perimeter of the region inside r=5sin(theta) but outside r=1.1=5sin(theta) theta=arcsin(1/5)
    1. answers icon 1 answer
    2. Joe asked by Joe
    3. views icon 1,195 views
  6. 40. Express4 cos 𝑥 + 3 sin 𝑥 in the form Rsin(𝑥 + 𝜃) A. 5Sin(x+36.9) B. 5Sin(x+53.1) C. 7Sin(x+36.9) D. 7Sin(x+53.1)
    1. answers icon 1 answer
    2. Benny asked by Benny
    3. views icon 148 views
  7. Use midpoints to approximate the area under the curve y = f(x) = 5sin(pi x) + 2.5cos(4pi x) on the interval [0, 1] using 10
    1. answers icon 1 answer
    2. Jessy asked by Jessy
    3. views icon 1,121 views
  8. An analog input signal x(t) = 1.5 + 1.5sin(5t) is sampled with 1 kHz sampling frequency fs. Assuming that sampling starts at t =
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 124 views
  9. Y=5sin(3.14(x-3.14/4))
    1. answers icon 1 answer
    2. Noah asked by Noah
    3. views icon 437 views
  10. If 5sin
    1. answers icon 1 answer
    2. Bandana gupta asked by Bandana gupta
    3. views icon 407 views