Why is the equivalence point

  1. How do you figure equivalence volume? Do I add up all of the additions during my lab up to the point I am measuring (color
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    2. Thomas asked by Thomas
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  2. 35.0 mL of a 0.250 M solution of KOH is titrated with 0.150 M HCl. After 35.0 mL of the HCl has been added, the resultant
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    2. Chemistry 101 asked by Chemistry 101
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  3. 35.0 mL of a 0.250 M solution of KOH is titrated with 0.150 M HCl. After 35.0 mL of the HCl has been added, the resultant
    1. answers icon 2 answers
    2. Shiro asked by Shiro
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  4. In this case, the inflection point, andequivalence, occurs after 23.25mL of 0.40 M NaOH has been delivered. Moles of base at the
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    2. John asked by John
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  5. The number of moles NaOH needed to reach the equivalence point ismol, which means we must add liters of NaOH. The total volume
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    2. Elizabeth asked by Elizabeth
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  6. Which of the following statements is true concerning the titration of a weak base by a solution of hydrochloric acid?Question 9
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    2. Anonymous asked by Anonymous
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  7. A 60.00 ml aliquot of a week acid HA is titrated with0.1000M NaOH. The equivalence volume is 30.00 ml. pH at the equivalence
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    2. ngo asked by ngo
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  8. L Let A = {1,2,3,4,5,6,7,8} and define an equivalence relation by a-b if and only if a-b is divisible by 3. Verify that this is
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  9. Explain why the volume of 0.100 M NaOH required to reach the equivalence point in the titration of 25.00 mL of 0.100 M HA is the
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    2. kobe asked by kobe
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  10. 3.14M NaN3 (pKb=9.28) is titrated with .663M HClO4 until it reaches the equivalence point. How do you calculate the pOH at the
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    2. sreedevi asked by sreedevi
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