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When 0.40 g of impure

A sample of impure magnesium was analyzed by allowing it to react with excess HCl solution:Mg(s) + 2 HCl(aq) → MgCl2(aq) +
1. 2 answers
2. asked by James
3. 4,565 views
Aiieeee!Todays lab...good grief. I was supposed to dissolve 0.3g of impure sulfanilamide in enough ethyl alchohol (95%) and me
1. 6 answers
2. asked by ~christina~
3. 722 views
A sample of impure magnesium was allowed to react with excess HCL solution. After 5.5 gram of the impure metal was treated with
1. 1 answer
2. asked by Anonymous
3. 659 views
calculate the mass of impure KOH needed to make up 1.20 L of 0.60 mol/L KOH(aq)? Assume the impure KOH is 84% KOH by mass and
1. 1 answer
2. asked by LG
3. 590 views
25cm3 of 0.1 mole H2SO4 neutralizes 20.0cm3 of impure NaOH containing 3.0g of impure NaOH in 250cm3 Of a solution . calculate
1. 1 answer
2. asked by Basil salvation
3. 531 views
A is a solution of hydrochloric acid containing 3.650g of HCl in 1dm3 of solution. B is asolution of impure sodium carbonate.
1. 1 answer
2. asked by Victor
3. 1,381 views
D is a solution containing 0.05mol/dm3 of H2SO4E is a solution containing 7.50g/dm3 of impure KOH Solution D was titrated
1. 1 answer
2. asked by Aminah
3. 463 views
The mass of potassium iodate (KIO3) contained in an impure sample was determined by titration with sodium thiosulfate (0.1005
1. 5 answers
2. asked by Gemma
3. 875 views
The mass of potassium iodate (KIO3) contained in an impure sample was determined by titration with sodium thiosulfate (0.1005
1. 3 answers
2. asked by Ami
3. 835 views
Impure sample of table salt that weighed 0.8421g, when dissolved in water and treated with excess AgNO3, formed 2.044g of AgCl.
1. 1 answer
2. asked by London
3. 2,057 views