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Using the equations R(x)=-x^2+400x and

  1. Using the equations R(x)=-x^2+400x and C(x)=x^2+40x+100, find the Maximum Revenue
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    2. Lindsay asked by Lindsay
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  2. Find the maximum revenue using the following equations: R(x)=-x^2 +400x and C(x)=x^2+40x+100.What I've done so far is use R(x)
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    2. Lindsay asked by Lindsay
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  3. the population of the city of Woodville is growing at a constant rate. The expression 38,000 +2, 400x models Woodville's
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    2. Lee Hooni 🖤 asked by Lee Hooni 🖤
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  4. Check my work? The equations given were R(x)=-x^2+400x and C(x)=x^2+40x+100. We were asked to find the maximum profit and
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    2. Lindsay asked by Lindsay
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  5. Solve. Click Here for Help Video.x2=400x^2={400}x 2 =400
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  6. solve the following quadratic100x^4=400x^3+2100x^2
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    2. Jodie asked by Jodie
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  7. A point charge, q= 400x 10 C, is placed on the x-axis at the origin. What is the electric field produced at x = 25.0 cm²in
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  8. A point charge, q= 400x 10^-9 C, is placed on the x-axis at the origin. What is the electric field produced at x = 25.0 cm²in
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    2. - asked by -
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  9. The point (0, 2) is the only solution to the system of linear equations that contains the equationsy = x + 2 and y = -3x + 2.
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    2. jae asked by jae
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  10. The table shows four equations found on an 8th grade math test.Which of the equations are linear functions? A Equation A only B
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    2. doogie asked by doogie
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