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Using log2=.3010 and log5=.6990 compute
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Using log2=.3010 and log5=.6990 compute
log2000000. 100000/5 = 20000 so I just did 20000*.699 = 13980 and then added .301 which
3 answers
asked by
Ann
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Given that log 2 =0.3010 , log 3 =0.4771 and log5 = 0.6990 , find log 6.5 + log 4
3 answers
asked by
Kenny Afams
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Express as a logarithm of a single number or expression:
1. 5log4^p+log4^q 2. log10^x-4 log10^y 3. 4log3^A-1/2 log3^B 4.
1 answer
asked by
Brandon
907 views
Given log2=0.3010, log3=0.4771, log5=0.6690, and log7=0.8451...
Find a.) log8 b) log5/7 c.) log1.5 d.) log3/14 e) log12 I didn't
2 answers
asked by
Katie
809 views
Given that log3=0.4771 and log5=0.6690 and log2=0.3010. Without using tables or calculators evaluate log0.243
2 answers
asked by
Ronnie
1,515 views
If log 2=0.3010,log 3=0.477 and log 5=0.6990 find log 25+log 9
1 answer
57 views
Given the log2 =0.3010 and log3=0.4771 calculatewithout using mathematical tables or calculator the value of
a.log54 b.log2.4
5 answers
asked by
Ella
226 views
If log 2=0.3010,log 3=0.4771 and log 5=0.6990 find log 36
1 answer
74 views
If log 2=0.3010,log 3= 0.4771 and log 5=0.6990 find log(0.125)
1 answer
76 views
2log15
Given that: Log=0.3010 Log=0.6990 Log=0.4771
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asked by
Nathaniel
302 views
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