Using log2=.3010 and log5=.6990 compute

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  1. Using log2=.3010 and log5=.6990 computelog2000000. 100000/5 = 20000 so I just did 20000*.699 = 13980 and then added .301 which
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    2. Ann asked by Ann
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  2. Given that log 2 =0.3010 , log 3 =0.4771 and log5 = 0.6990 , find log 6.5 + log 4
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    2. Kenny Afams asked by Kenny Afams
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  3. Express as a logarithm of a single number or expression:1. 5log4^p+log4^q 2. log10^x-4 log10^y 3. 4log3^A-1/2 log3^B 4.
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    2. Brandon asked by Brandon
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  4. Given log2=0.3010, log3=0.4771, log5=0.6690, and log7=0.8451...Find a.) log8 b) log5/7 c.) log1.5 d.) log3/14 e) log12 I didn't
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    2. Katie asked by Katie
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  5. Given that log3=0.4771 and log5=0.6690 and log2=0.3010. Without using tables or calculators evaluate log0.243
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    2. Ronnie asked by Ronnie
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  6. If log 2=0.3010,log 3=0.477 and log 5=0.6990 find log 25+log 9
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  7. Given the log2 =0.3010 and log3=0.4771 calculatewithout using mathematical tables or calculator the value ofa.log54 b.log2.4
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    2. Ella asked by Ella
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  8. If log 2=0.3010,log 3=0.4771 and log 5=0.6990 find log 36
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  9. If log 2=0.3010,log 3= 0.4771 and log 5=0.6990 find log(0.125)
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  10. 2log15Given that: Log=0.3010 Log=0.6990 Log=0.4771
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    2. Nathaniel asked by Nathaniel
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