Under acidic conditions, MnO4− becomes

Under acidic conditions, MnO4− becomes Mn2+. Write the balanced half-reaction for this transformation. (Omit states-of-matter
1. 4 answers
2. asked by Tsion
3. 4,480 views
For the following electrochemical cell:Fe(s) Fe2+(aq) MnO4–(aq) Mn2+(aq) Pt(s) Which letter corresponds to the correct
1. 1 answer
2. asked by Anonymous
3. 1,318 views
For the following electrochemical cell:Fe(s) Fe2+(aq) MnO4–(aq) Mn2+(aq) Pt(s) Which letter corresponds to the correct
1. 1 answer
2. asked by Anonymous
3. 730 views
Balance the following oxidation-reduction reactions, which occur in acidic solution, using the half-reaction method. (Use the
1. 1 answer
2. asked by Anonymous
3. 655 views
I would like to check my answer to the following question:The permanganate ion oxidizes bromide in acidic conditions to form
1. 11 answers
2. asked by Kelsy
3. 2,066 views
Consider the following half-reactions:MnO4- + 8H+ + 5e- --> Mn2+ + 4H2O NO3- + 4H+ + 3e- --> NO + 2H2O Predict whether NO3- ions
1. 2 answers
2. asked by Anonymous
3. 3,561 views
In a particular redox reaction, MnO2 is oxidized to MnO4– and Cu2 is reduced to Cu . Complete and balance the equation for
1. 6 answers
2. asked by BOB
3. 9,466 views
Hey i have a question regarding disproportionate reactions:Permanganate ions MnO4 reacts with oxalic acid, H2C2O4 in acidic
1. 2 answers
2. asked by Sara
3. 1,422 views
Balance the following equations and show the steps:1. MnO4- + C2O42- = Mn2+ + CO2 2. NO2- + MnO4- = NO3- + Mn2+ (in acid
1. 3 answers
2. 195 views
Balance the following equations:1. MnO4- + C2O42- = Mn2+ + CO2 2. NO2- + MnO4- = NO3- + Mn2+ (in acid Solution) 3. I- + MnO4- =
1. 5 answers
2. 148 views