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U-Substitution 1. 3x(sin^2((3x^2)+1)cos((3x^2)+1)dx 2. (x^3)(sqrt((3x^2)+1))
Integral of:
__1__ (sqrt(x)+1)^2 dx The answer is: 2ln abs(1+sqrt(x)) + 2(1+sqrt(X))^-1 +c I have no clue why that is! Please
0 answers
asked by
Gabriela
1,146 views
Calculate definite integral of
dx/(x^4 * sqrt(x^2 + 3)) Over (1,3) I start with the substitution x = sqrt(3)*tan t so: sqrt(x^2 +
2 answers
asked by
mathstudent
668 views
Find ∫1/((x^2+5)^(3/2)) dx
I figured this would be a trig substitution problem, so I set x = sqrt(5)tanθ and dx =
3 answers
asked by
Ray
601 views
Using integration by substitution.
find the exact value of integral from [0,9/16] sqrt(1 - sqrt(x))/(sqrt(x))
1 answer
asked by
Alex
451 views
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.
sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
1 answer
asked by
Alexa
3,206 views
Find the integral from 0 to 2 of xsqrt(5-sqrt4-x^2)).
The hint said to use substitution of u=sqrt(4-x^2), and that I needed one
4 answers
asked by
Henry
640 views
Evaluate the integral from
[sqrt(pi/2), sqrt(pi)] of x^3*cos(x^2) by first making a substitution and then using integration by
1 answer
asked by
Dave
796 views
sqrt 6 * sqrt 8
also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So you can see the steps — sqrt 6 * sqrt 8 = sqrt 48 sqrt 7 *
0 answers
asked by
Tina
744 views
Which of the following measurements could be the side lengths of a right triangle?
A. /sqrt{126}in, /sqrt{54} in, /sqrt{63}in B.
1 answer
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Optional
100 views
(- 3, 5)
X (7, - 1) Find the distance between these two points using the Pythagorean Theorem. Which choice is correct? (1 point)
1 answer
85 views