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This question has me stuck. Use the Pythagorean identity sin^2
This question has me stuck. Use the Pythagorean identity sin^2 Θ + cos^2 Θ = 1 to derive the other Pythagorean identities, 1 +
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asked by
Iris
1,126 views
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Use the polynomial identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to generate a Pythagorean triple when x equals 7 and y
2 answers
91 views
Prove each identity:
a) 1-cos^2x=tan^2xcos^2x b) cos^2x + 2sin^2x-1 = sin^2x I also tried a question on my own: tan^2x = (1 –
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asked by
Kate
650 views
Use the Pythagorean Identity first and then the Tangent Identity to find tanθ if cosθ=-1/2 and θ terminates in Quadrant II.
1 answer
49 views
Use the polynomial identity (x2+y2)2=(x2−y2)2+(2xy)2
to generate a Pythagorean triple when x equals 7 and y equals 4. Write the
1 answer
asked by
jim
44 views
Mei wants to generate a Pythagorean triple when x equals 8 and y equals 6 using the polynomial identity
1 answer
asked by
jim
31 views
Use the Pythagorean identity, Latex: (x^2-y^2)^2+(2xy)^2=(x^2+y^2)^2\textsf{,} to create a Pythagorean triple
choose two numbers
1 answer
asked by
Anna
90 views
Ashley wants to generate a Pythagorean triple when x = 11 and y = 4 using the polynomial identity (x2+y2)2 = (x2−y2)2+(2xy)2 .
1 answer
6 views
Ashley wants to generate a Pythagorean triple when x = 18 and y = 9 using the polynomial identity (x2+y2)2 = (x2−y2)2+(2xy)2 .
1 answer
7 views
Georgina is told that an angle has a sine of sqrt 5/5 and is in quadrant 2. Use the Pythagorean identity sin^2(0) + cos^2(0) =1,
1 answer
27 views