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A region is bounded by the function y=2x^2+3 and the x-axis over the interval(0,2). Sketch the graph of the bounded region. Use
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Anonymous
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find the volume of the solid bounded above by the surface z=f(x,y) and below by the plane region R
f(x,y)=2x^2 y;R is the region
2 answers
asked by
sol
1,197 views
Write the integral in one variable to find the volume of the solid obtained by rotating the firstâquadrant region bounded by y
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Hannah
1,456 views
Consider the region in Quadrant 1 totally bounded by the 4 lines: x = 3, x = 9, y = 0, and y = mx (where m is positive).
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borat
707 views
Consider the region in Quadrant 1 totally bounded by the 4 lines: x = 3, x = 9, y = 0, and y = mx (where m is positive).
1 answer
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borat
549 views
Consider the region in Quadrant 1 totally bounded by the 4 lines: x = 3, x = 9, y = 0, and y = mx (where m is positive).
0 answers
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borat
544 views
'Find the volume of the solid generated by revolving the region bounded by x=16-y^2, x-axis, and y-axis around the x-axis.'
I
2 answers
asked by
CodyL
704 views
1)What is the area bounded by y = x^2 and y =3x?
A)5 B)9/2 ***C)8 D)11.2 E)25 i believe it to be 8 but im not sure. 2)The region
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asked by
ReviewDay :(
786 views
1. Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the line x = 6.
y
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asked by
Mark
1,852 views
The region R is the region in the first quadrant bounded by the curves y=x^ 2 -4x+ 4, x = 0 , and x = 2, as seen in the image
2 answers
asked by
Slaya
911 views