The problem is factoring completely

The problem is factoring completely4xX^2-20x-24 4(X^2-5x-60 4(x-6)(x+1) 12x^2-75 3(X^2-25)=3(X-25)(x+3) Can someone check these
1. 1 answer
2. asked by Betty C
3. 488 views
factoring completely, state that the polynomials is prime.x^-16 (x+8)(x-8) not prime. x^-8x+12 x(8x+12) (4x+6) Check these
1. 3 answers
2. asked by Ashley
3. 499 views
can someone check these for me please....problem#4 Directions: Factor each polynomial completely by factoring out any common
1. 0 answers
2. asked by jas20
3. 1,171 views
can i use factoring to simplify this trig identity?the problem is sinx + cotx * cosx i know the answer is cscx and i know how to
1. 4 answers
2. asked by v
3. 783 views
factoring completely:36x^2 + 60x +25
1. 1 answer
2. asked by Sabrina
3. 902 views
Factoring by Using a Quadratic FormProblem: x^4 + 8x^2 - 20 What I have so far: (x^2)^2 + 8(x^2) - 20 a^2 + 8a - 20 For some
1. 1 answer
2. asked by Mike
3. 636 views
Factoring the following polynomial expression completely:2 x 3 + x 2 − 8 x − 4 2x 3 +x 2 −8x−4
1. 1 answer
2. 19 views
Factoring the following polynomial expression completely:2 x 3 + x 2 − 8 x − 4 2x 3 +x 2 −8x−4
1. 1 answer
2. 16 views
Is x (4x2 + 8x + 12) completely factored? If not, what other factoring can occur?
1. 1 answer
2. 61 views
Factoring Trinomials (a = 1)Factors each completely. b^2 + 8b + 7
1. 1 answer
2. asked by Mujeeb Shaikh
3. 101 views