The half-equivalence point of a

  1. The half-equivalence point of a titration occurs half way to the end point, where half of the analyte has reacted to form its
    1. answers icon 0 answers
    2. sara asked by sara
    3. views icon 839 views
  2. The half-equivalence point of a titration occurs half way to the end point, where half of the analyte has reacted to form its
    1. answers icon 1 answer
    2. Felicia asked by Felicia
    3. views icon 953 views
  3. The half-equivalence point of a titration occurs half way to the end point, where half of the analyte has reacted to form its
    1. answers icon 1 answer
    2. samm asked by samm
    3. views icon 6,323 views
  4. Consider a 20.0mL sample of 0.105M HC2H3O2 is titrated with 0.125M NaOH.Ka=1.8x10^-5. Determine each of the following: a) the
    1. answers icon 7 answers
    2. bobjahng2 asked by bobjahng2
    3. views icon 1,954 views
  5. A 30 mL sample of .165 M propanoic acid is titrated with .300M KOH. Calculate the pH at each volume of added base: 0 mL, 5 mL,
    1. answers icon 2 answers
    2. Anonymous asked by Anonymous
    3. views icon 1,873 views
  6. Assuming that Ka is 1.85 *10-5 for acetic acid, calculate the pH at one-half the equivalence point and at the equivalence point
    1. answers icon 1 answer
    2. Kenetria asked by Kenetria
    3. views icon 2,600 views
  7. HC2H3O2 + NaOH --> NaC2H3O2 + H2O?a. when the titration is only half over, what species are present in the reaction flask b.
    1. answers icon 2 answers
    2. Anonymous asked by Anonymous
    3. views icon 2,376 views
  8. How do you figure equivalence volume? Do I add up all of the additions during my lab up to the point I am measuring (color
    1. answers icon 2 answers
    2. Thomas asked by Thomas
    3. views icon 523 views
  9. 35.0 mL of a 0.250 M solution of KOH is titrated with 0.150 M HCl. After 35.0 mL of the HCl has been added, the resultant
    1. answers icon 2 answers
    2. Shiro asked by Shiro
    3. views icon 2,449 views
  10. 35.0 mL of a 0.250 M solution of KOH is titrated with 0.150 M HCl. After 35.0 mL of the HCl has been added, the resultant
    1. answers icon 0 answers
    2. Chemistry 101 asked by Chemistry 101
    3. views icon 490 views