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The curve y =|x|/(sqrt(5−x^2)) is
Find the area of the surface of revolution generated by revolving the curve y = 3 sqrt (x), 0 <= x <= 4, about the x-axis.
Okay,
1 answer
asked by
Anon
2,255 views
Given the curve defined by the equation y=cos^2(x) + sqrt(2)* sin(x) with domain (0,pi) , find all points on the curve where the
1 answer
asked by
Ashok
682 views
The curve y =|x|/(sqrt(5−x^2))
is called a bullet-nose curve. Find an equation of the tangent line to this curve at the point
1 answer
asked by
TayB
856 views
The curve y = |x|/(sqrt(5- x^2)) is called a bullet-nose curve. Find an equation of the tangent line to this curve at the point
2 answers
asked by
TayB
6,090 views
Compute the area of the region in the fi…rst quadrant bounded
on the left by the curve y = sqrt(x), on the right by the
1 answer
asked by
bob
654 views
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.
sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
1 answer
asked by
Alexa
3,171 views
Find the point on the curve y=x^2 closest to point (0,1)
Here's what I have: Sqrt {(x-0)^2 + ((x^2)-1)} Sqrt {((x^2) + (x^2)-1}
4 answers
asked by
Mandy
1,120 views
sqrt 6 * sqrt 8
also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So you can see the steps — sqrt 6 * sqrt 8 = sqrt 48 sqrt 7 *
0 answers
asked by
Tina
706 views
Use implicit differentiation to find the slope of the tangent line to the curve sqrt of x + sqrt of y = 8
1 answer
asked by
gnozahs
1,362 views
find the slope of the tangent line to the curve (sqrt 2x+4y) + (sqrt 4xy) = 9.16
at the point (1,5) dy/dx method implicit
1 answer
asked by
sal
824 views