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The base dissociation equilibrium constant

The base dissociation equilibrium constant (Kb) for C5H5N is 1.40×10-9 (eq. 1).(eq. 1): C5H5N(aq) + H2O(l) = OH-(aq) +
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2. asked by sparkle
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Can somone please explain this problem to me? The hydrolysis equilibrium constant (Ka) for NH2NH3+ is 5.88E-9 (eq. 1).(eq. 1):
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2. asked by John
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for a solution of the weak base, 0.075 M ethylamine C2H5NH2(aq), the hydroxide ion concentration (OH-) is 6.6x10^-3 M. Assume
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2. asked by Sharon
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The equilibrium constant for thermal dissociation of F2F2(g)<->2F(g) is 0.300. If initially 1.00 mol F2 is placed in a 1.00 L
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2. asked by Gabriella
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Now use the average value of Kb the base dissociation constant of acetate anion to calculate an average value for Ka, the acid
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2. asked by Jenn
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The acid-dissociation constant, Ka, for gallic acid is 4.57 × 10-3. What is the base-dissociation constant, Kb, for gallate
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2. asked by jessica
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MnS(s) + 2 H+ --> Mn2+ + H2S(g)At 25 C the solubility product constant, Ksp, for MnS is 5 x 10-15 and the acid dissociation
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2. asked by AL
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What is the value of the equilibrium constant for the dissociation of acetic acid's proton? What does this value tell you?
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2. asked by tara
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Consider the dissociation of ammonia in water at equilibrium:NH3 + H2O ↔ NH4+ + OH– You start with 0.05 moles of ammonia in
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2. asked by Samy
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What would happen to a weak base dissociation equilibrium if more products were added?
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2. asked by princess
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