Ask a New Question

The base dissociation equilibrium constant

The base dissociation equilibrium constant (Kb) for C5H5N is 1.40×10-9 (eq. 1).(eq. 1): C5H5N(aq) + H2O(l) = OH-(aq) +
1. 1 answer
2. asked by sparkle
3. 4,732 views
Can somone please explain this problem to me? The hydrolysis equilibrium constant (Ka) for NH2NH3+ is 5.88E-9 (eq. 1).(eq. 1):
1. 1 answer
2. asked by John
3. 1,202 views
for a solution of the weak base, 0.075 M ethylamine C2H5NH2(aq), the hydroxide ion concentration (OH-) is 6.6x10^-3 M. Assume
1. 3 answers
2. asked by Sharon
3. 823 views
The equilibrium constant for thermal dissociation of F2F2(g)<->2F(g) is 0.300. If initially 1.00 mol F2 is placed in a 1.00 L
1. 1 answer
2. asked by Gabriella
3. 1,241 views
Now use the average value of Kb the base dissociation constant of acetate anion to calculate an average value for Ka, the acid
1. 1 answer
2. asked by Jenn
3. 3,225 views
The acid-dissociation constant, Ka, for gallic acid is 4.57 × 10-3. What is the base-dissociation constant, Kb, for gallate
1. 1 answer
2. asked by jessica
3. 1,618 views
MnS(s) + 2 H+ --> Mn2+ + H2S(g)At 25 C the solubility product constant, Ksp, for MnS is 5 x 10-15 and the acid dissociation
1. 3 answers
2. asked by AL
3. 5,403 views
What is the value of the equilibrium constant for the dissociation of acetic acid's proton? What does this value tell you?
1. 0 answers
2. asked by tara
3. 400 views
Consider the dissociation of ammonia in water at equilibrium:NH3 + H2O ↔ NH4+ + OH– You start with 0.05 moles of ammonia in
1. 6 answers
2. asked by Samy
3. 1,499 views
What would happen to a weak base dissociation equilibrium if more products were added?
1. 1 answer
2. asked by princess
3. 969 views