Tanx + sinxsecx/ cscxtanx

  1. Tanx + sinxsecx/ cscxtanx
    1. answers icon 1 answer
    2. Kristen asked by Kristen
    3. views icon 1,215 views
  2. Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 1,407 views
  3. Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
    1. answers icon 4 answers
    2. Anonymous asked by Anonymous
    3. views icon 2,004 views
  4. For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows;
    1. answers icon 5 answers
    2. CodyJinks asked by CodyJinks
    3. views icon 817 views
  5. Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
    1. answers icon 1 answer
    2. Marrion asked by Marrion
    3. views icon 739 views
  6. Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
    1. answers icon 0 answers
    2. Marrion asked by Marrion
    3. views icon 739 views
  7. 2tan^2x-tanx-1=00<x<2pi •MATH - Steve, Thursday, July 18, 2013 at 11:48am (2tanx+1)(tanx-1) = 0 tanx = -1/2 or 1 ... Recall in
    1. answers icon 5 answers
    2. ROBIN asked by ROBIN
    3. views icon 645 views
  8. Perform the addition or subtraction.tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the
    1. answers icon 1 answer
    2. Hannah asked by Hannah
    3. views icon 824 views
  9. Derivative of y=sec(tanx)?I don't get how it is secxsecx*secxtanx*tanxtanx. Where does an extra tanx come from? Derivative of
    1. answers icon 1 answer
    2. Beth asked by Beth
    3. views icon 804 views
  10. Did I do this problem right?Find the first and second derative-simplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'=
    1. answers icon 1 answer
    2. Janet asked by Janet
    3. views icon 729 views