Suppose x=4sin(theta, for theta (-pie/2,

  1. Which is a polar form of the following parametric equations ?x=4sin^2 theta Y=4 sin theta cos theta a) r=1/4sin theta cod theta
    1. answers icon 1 answer
    2. views icon 72 views
  2. which is a polar form of the following parametric equations?x=4sin^2(theta) y=4 sin(theta) cos (theta) *r=1/4
    1. answers icon 1 answer
    2. bobby asked by bobby
    3. views icon 55 views
  3. Suppose that \Theta takes values in [0,1] and its PDF is of the formf_{\Theta }(\theta )= a\theta (1-\theta )^2,\ \ \
    1. answers icon 1 answer
    2. views icon 357 views
  4. 1. Show that Sin3 Theta - Cos2 Theta = (1 - Sin Theta)(4Sin^2 Theta + 2Sin Theta - 1).Without using a calculator, show that
    1. answers icon 0 answers
    2. Edwards asked by Edwards
    3. views icon 601 views
  5. I am having problems with proving identities that has a number and an exponent with it.Like: *2cosxcsc2x = cscx *sin^2 2x =
    1. answers icon 1 answer
    2. Jam asked by Jam
    3. views icon 836 views
  6. Multiple Choice (theta) means the symbol 0 with the dash in it.1.)Which expression is equivalent to
    1. answers icon 2 answers
    2. HotMath asked by HotMath
    3. views icon 1,489 views
  7. Multiple ChoiceWhich expression is NOT equivalent to 1? (theta) means 0 with dash in it. A.)sin^2 (theta)+cot^2 (theta) sin^2
    1. answers icon 0 answers
    2. HotMath asked by HotMath
    3. views icon 816 views
  8. Thank you STEVE!!!!!Suppose that Cos (theta) = 1/square root 2 if 0<equal to theta , pi/2 then sin(theta) = tan (theta) = If
    1. answers icon 1 answer
    2. George asked by George
    3. views icon 1,107 views
  9. Justin wants to evaluate 3cot(-5pi/4). Which of the following identities can he use to help him? Select two answers.cot(-theta)
    1. answers icon 5 answers
    2. Max asked by Max
    3. views icon 2,741 views
  10. write the following parametric equations as a polar equationx=t^2 y=2t *r=4cot(theta)csc(theta) *r=2cot(theta)csc(theta)
    1. answers icon 1 answer
    2. heheeeee asked by heheeeee
    3. views icon 73 views