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StartFraction 5 Over s Superscript

Simplify the following exponential expression.StartFraction 243 y Superscript 5 Baseline z Superscript 8 Over negative 27 y
1. 1 answer
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Use the quotient rule to simplify the expression. Assume that all bases are not equal to 0.StartFraction p Superscript 5
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2. 88 views
Which is equivalent to RootIndex 5 StartRoot 1,215 EndRoot Superscript x?243x 1,215 Superscript one-fifth x 1,215 Superscript
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2. asked by Christine
3. 311 views
Simplify the expression.StartFraction 8 z Superscript negative 1 Baseline x Superscript negative 2 Over p Superscript 0
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2. 105 views
Divide and simplify.StartFraction h Superscript negative 3 Over h Superscript negative 6 EndFraction . . . Question content area
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2. 53 views
Which is equivalent to StartFraction x Superscript 3 Baseline over StartRoot x EndRoot EndFraction?Answer options with 5 options
1. 1 answer
2. 48 views
Which is the simplified form of n Superscript negative 6 p cubed?StartFraction n Superscript 6 Over p cubed EndFraction
1. 3 answers
2. 177 views
Which expression is equivalent to StartFraction x Superscript StartFraction 4 over 3 EndFraction Baseline over x Superscript
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2. asked by eeeeee
3. 35 views
Which expression is equivalent to x Superscript StartFraction 2 over 3 EndFraction Baseline plus StartFraction 1 over x
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2. asked by I LOVE BIG BLACK MUSCULAR MEN
3. 28 views
Which expression is equivalent to a Superscript StartFraction 1 over 3 EndFraction Baseline plus StartFraction 2 over a
1. 1 answer
2. asked by eeeeee
3. 45 views