Solve. sqrt of b^4/25=4 A.

When I solve the inquality 2x^2 - 6 < 0,I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or
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2. asked by Jen
3. 1,361 views
So I am supposed to solve this without using a calculator: Sqrt[20]/10 - Sqrt[10]/Sqrt[32] - Sqrt[0.3125] + Sqrt[3 + 1/5]You can
1. 2 answers
2. asked by Mr.AMG
3. 917 views
Solve in the exact form.(sqrt of 4x+1)+(sqrt of x+1)=2 Someone showed me to do this next: Square both sides..so.. 4x+1+2((sqrt
1. 4 answers
2. asked by Gingie
3. 1,234 views
Could someone show me how to solve these problems step by step....I am confused on how to fully break this down to simpliest
1. 1 answer
2. asked by Reggie
3. 1,430 views
Could some kind, saintly soul help me solve this problem?Simplify: 8w sqrt(48w^5) - x^2 sqrt(3xw^2) . .
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2. asked by Maria
3. 820 views
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
1. 1 answer
2. asked by Alexa
3. 3,278 views
Solve the quadratic equation 6x^2-3x+6=0. Which of the following expresses its solutions in the form a± bi ? (1 point) 1/4 ±
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2. 66 views
Please look at my work below:Solve the initial-value problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/-
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2. asked by COFFEE
3. 961 views
sqrt 6 * sqrt 8also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So you can see the steps — sqrt 6 * sqrt 8 = sqrt 48 sqrt 7 *
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2. asked by Tina
3. 830 views
Solve the initial-value problem.y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/- Sqrt(4^2-4(1)(6)))/2(1) r=(16
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2. asked by COFFEE
3. 931 views