Solve the equation. 2 sinx

solve each equation for 0=/<x=/<2pisin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx - 3)(sinx
1. 7 answers
2. asked by sh
3. 943 views
the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
1. 3 answers
2. asked by alex
3. 859 views
Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
1. 3 answers
2. asked by Anonymous
3. 936 views
Solving Trigonometic Equationssolve for x and give the answers as a equations : ( by radian) 1)cos(sinx)=1 <<<and thanks >>> We
1. 0 answers
2. asked by abdo
3. 679 views
Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
1. 1 answer
2. asked by Maggie
3. 829 views
solve equation for exact solution if possible leave answer in degreesinx/2=square root of 2- sinx/2
1. 1 answer
2. asked by mike
3. 369 views
Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
1. 3 answers
2. asked by Anonymous
3. 775 views
1) Solve the equationsinx(sinx+1) = 0 I am having trouble with the first step. Could I do sin x^2 + 1 =0?
1. 1 answer
2. asked by Abby
3. 490 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
1. 0 answers
2. asked by shan
3. 976 views
How would I solve this equation for x in the interval 0<x<2pitan^2x sinx - sinx/3 = 0 Please explain it step by step..ive been
1. 3 answers
2. asked by Diana
3. 518 views