Solve the equation cotΘ-abtanΘ =

Solve the equationcotΘ-abtanΘ = a-b Answer-tanΘ=1/a or -1/b
1. 1 answer
2. asked by Kewal
3. 459 views
For the acute angle θ, given that sinθ=1/7, find the exact value of cotθ.cotθ=1/√48 cotθ=1/√50 cotθ=√50 cotθ=√48
1. 1 answer
2. asked by Stephanie
3. 434 views
Find the exact value of cotθ given secθ=3 and tanθ<0.cotθ=8√/3 cotθ=−(3/√8) cotθ=1/√8 cotθ=−(√8/3)
1. 3 answers
2. asked by Stephanie
3. 375 views
given cotθ = (1/2) √7, find sinθ and cosθ in quadrant Icotθ = x/y would 1/2 be the x and √7 be the y?
1. 0 answers
2. asked by coco
3. 475 views
Simplify the expression (tanθ+cotθ)^2 - (tanθ-cotθ)^2 using algebra and trigonometric identities.
1. 1 answer
2. asked by Bob
3. 871 views
Prove the following identities:a) (cosec θ + cotθ)(cosecθ - cotθ) = cotθtanθ b) 2/(1 + sinθ) + 1/(1- sinθ) = (3sec^2)θ
1. 2 answers
2. asked by Proving Identities Question (Trig.)
3. 764 views
Can someone tell me how to do this problem?(sin^2 θ - cotθ * tan θ)/ cotθ * sin θ Please and thank you.
1. 2 answers
2. asked by Ana
3. 453 views
1) given cotθ = 1/2√7, find sinθ and cosθ in quadrant I2) given tanθ = √5, find secθ and cotθ in quadrant III
1. 4 answers
2. asked by coco
3. 845 views
#1 cscθ-cotθ#2 cosθ(tanθ-secθ) #3 tanθ+sinθ/cscθ+cotθ
1. 3 answers
2. asked by lucy
3. 895 views
Enter your answer and show all the steps that you use to solve this problem in the space provided.Verify the basic identity.
1. 1 answer
2. 85 views