Solve the equation cotΘ-abtanΘ =

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Solve the equationcotΘ-abtanΘ = a-b Answer-tanΘ=1/a or -1/b
1. 1 answer
2. asked by Kewal
3. 418 views
For the acute angle θ, given that sinθ=1/7, find the exact value of cotθ.cotθ=1/√48 cotθ=1/√50 cotθ=√50 cotθ=√48
1. 1 answer
2. asked by Stephanie
3. 393 views
Find the exact value of cotθ given secθ=3 and tanθ<0.cotθ=8√/3 cotθ=−(3/√8) cotθ=1/√8 cotθ=−(√8/3)
1. 3 answers
2. asked by Stephanie
3. 324 views
given cotθ = (1/2) √7, find sinθ and cosθ in quadrant Icotθ = x/y would 1/2 be the x and √7 be the y?
1. 0 answers
2. asked by coco
3. 419 views
Simplify the expression (tanθ+cotθ)^2 - (tanθ-cotθ)^2 using algebra and trigonometric identities.
1. 1 answer
2. asked by Bob
3. 822 views
Prove the following identities:a) (cosec θ + cotθ)(cosecθ - cotθ) = cotθtanθ b) 2/(1 + sinθ) + 1/(1- sinθ) = (3sec^2)θ
1. 2 answers
2. asked by Proving Identities Question (Trig.)
3. 697 views
Can someone tell me how to do this problem?(sin^2 θ - cotθ * tan θ)/ cotθ * sin θ Please and thank you.
1. 2 answers
2. asked by Ana
3. 428 views
1) given cotθ = 1/2√7, find sinθ and cosθ in quadrant I2) given tanθ = √5, find secθ and cotθ in quadrant III
1. 4 answers
2. asked by coco
3. 786 views
#1 cscθ-cotθ#2 cosθ(tanθ-secθ) #3 tanθ+sinθ/cscθ+cotθ
1. 3 answers
2. asked by lucy
3. 828 views
Enter your answer and show all the steps that you use to solve this problem in the space provided.Verify the basic identity.
1. 1 answer
2. 43 views