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Solve the equation Cos40° Cosx
Solve the equation
Cos40° Cosx + sin 40° sin x=square root 3/2
1 answer
asked by
Azeez
104 views
Solve the equation
Cos40° Cosx + sin 40° sin x=square root 3/2 for 0° less than or equal to x less than or equal to 360°
1 answer
asked by
Azeez
95 views
Solve this equation fo rx in the interval 0<=x<=360
3sinxtanx=8 I would do it this way: sinxtanx = 8/3 sinx(sinx/cosx)=8/3
0 answers
asked by
Edward
1,035 views
solve each equation for 0=/<x=/<2pi
sin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx - 3)(sinx
7 answers
asked by
sh
1,017 views
solve algebreically the equation
cos2x=1-sinx also cosx=cosx-1 and please also sin2x=3sinx
1 answer
asked by
adil ahmed
692 views
solve this equation on the given interval expressing the solution for x in terms of inverse trigonometric functions.
6(cosx)^2-co
3 answers
asked by
Josh
647 views
i am trying to solve for A and B....this question comes from a Differential equations...but this step goes back to basics...
Asin
2 answers
asked by
mary
659 views
Solve each equation for 0≤x<2π
1. (cosX)(cosX+1)=0 2. 2sin^2(X)-3sinX=2
1 answer
asked by
Leslie
544 views
How many solutions does the equation cosx + 1/2 = 1 have for 0<x<2pi
cosx+1/2=1 cosx+1=2 cosx=2-1 cosx=1 therefore 1 solution? A)
3 answers
asked by
Jake
1,968 views
Solve:
cos(2x-180) - sin(x-90)=0 my work: cos2xcos180 + sin2xsin180= sinxcos90 - sin90cosx -cos2x - sin2x= cosx -cos^2x + sin^2x
0 answers
asked by
Jess
830 views