Solve the equation 2cos(x)+1=0,0≤x≤2π0≤x≤2π. Show

Solve the equation 2cos(x)+1=0,0≤x≤2π0≤x≤2π. Show all of your work.
1. 2 answers
2. asked by rosie
3. 1,240 views
Solve the equation 2cos(x)+1=0, 0≤x≤2π . Show all of your work.
1. 1 answer
2. 77 views
Given that 2cos^2 x - 3sin x -3 = 0, show that 2sin^2 x + 3sin x +1 = 0?Hence solve 2cos^2 x + 4sin x - 3 = 0, giving all
1. 2 answers
2. asked by Sean
3. 983 views
2cos^2Beta-Cosbeta=0 (find all solutions for the equation in the interval 0, 2 pi). I have no idea how to go about doing this.
1. 2 answers
2. asked by Janie
3. 926 views
the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
1. 3 answers
2. asked by alex
3. 869 views
What am I doing wrong?Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
1. 1 answer
2. asked by Anonymous
3. 985 views
Solve the equation on the interval 0 less than or equals theta less than 2 pi 0≤θ<2π. 2cos^(2)\theta +\sqrt(2cos\theta
1. 1 answer
2. asked by Yana
3. 633 views
Solve the following equation for0 less than and/or equal to "x" less than and/or equal to 360 -- cos^2x - 1 = sin^2x -- Attempt:
1. 1 answer
2. asked by Anonymous
3. 849 views
1)Solve;2x+1/6=1/2x2)Solve for y in the equation;6y-4/3-2y-1/2=6-5y/6. 3)Solve the equation: 4 sin^2titre+4cos titre=5 for 0°
1. 1 answer
2. asked by Mary
3. 198 views
Show that the limit for [x^2cos(1/x)]=0 as x approaches 0.How would I solve this algebraically?
1. 1 answer
2. asked by John
3. 502 views