Solve that cos2x +sin2x=1 using

Solve identity,(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
1. 3 answers
2. asked by sh
3. 749 views
Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
1. 4 answers
2. asked by Brian
3. 797 views
solve for (<_ = less than or equal to / pie = pie sign / -pie = negative pie)3 sin²x = cos²x ; 0 <_ x < 2pie cos²x - sin²x =
1. 3 answers
2. asked by Julie
3. 1,075 views
sinx = 4/5 and x terminates in Quadrant IIFind sin2x and cos2x How to get the answers, which are sin2x = -24/25, cos2x = -7/25?
1. 1 answer
2. asked by Amandeep
3. 1,757 views
Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2x-cos2xive tried this problem so many times I need help with
1. 1 answer
2. asked by Maria
3. 1,532 views
prove sin2x+cos2x+1 tan(pi/4+x)______________ = __________ sin2x+cos2x-1 tanx so what I did tan(x)
1. 2 answers
2. asked by Lana
3. 751 views
Solve the equation 2cos2x = √3 for 0°≤x≤360°I did this: cos2x = √3 /2 2x=30 x=15 x=15, 165, 195, 345 Is this correct?
1. 1 answer
2. asked by Autumn
3. 1,794 views
Prove that sin2x+cos2x-1/sin2x+cos2x+1=tanx
1. 1 answer
2. asked by James
3. 1,246 views
prove that1+sin2x-cos2x / sin2x+cos2x = tanx
1. 1 answer
2. asked by Anonymous
3. 1,365 views
cotx = -2 and 0 less than or equal to x less than or equal to piFind sin2x and cos2x How to get the answers of sin2x = -4/5,
1. 1 answer
2. asked by Amandeep
3. 667 views