Ask a New Question
Search
Solve simultaneously the equations; log2
Solve simultaneously the equations;
log2 𝑥 − log2 𝑦 = −1 and log𝑦(6𝑥 + 𝑦) − log𝑦(4𝑥 − 𝑦) = 1 A.
1 answer
asked by
Benny
257 views
i need help with these two homework problems
Use the Laws of Logarithms to combine the expression into a single logarithm log2 5
1 answer
asked by
Emma
820 views
solve the equation
log2(x+4)-log4x=2 the 2 and 4 are lower than the g This is what I got: log2(x+4)+log2(4^x)=2 log2((x+4)*4^x)=2
1 answer
asked by
anonymous
1,042 views
1. Solve the following simultaneous equations:
log2 xy = 7 log2 (x^2/y) = 5 2. If log y x =a and log z x=b where x is not equal
5 answers
asked by
Claire
954 views
Solve the equations
i) log2(x + 2) + log2 x = 3. ii) 25^x + 5^x+1 + 6 = 0.
0 answers
asked by
MSM
528 views
solve log2(3x-1)-log2(x-1)=log2(x+1)
i have absolutely no idea how to solve this. can anyone help me, please?
1 answer
asked by
Kelly
526 views
Solve:
2^(5x-6) = 7 My work: log^(5x-6) = log7 5x - 6(log2) = log7 5x = log7 + 6(log2) x = (log7 + log2^6) / 5 And textbook
2 answers
asked by
Anonymous
1,221 views
Solve the equation log2 x + log2 (x + 4) - log2 (x - 2) = 4
1 answer
184 views
Hi! Could someone possibly help me solve this?; log2(x+4)=log2(x^2+2). For my answer, I got "All Real Numbers" or x=0 but I'm
1 answer
asked by
Sally
412 views
Hi! Could someone possibly help me solve this?; log2(x+4)=log2(x^2+2). For my answer, I got "All Real Numbers" or x=0 but I'm
1 answer
asked by
Sally
525 views