Solve for X: log4(3x-7)^2 =

Solve log4 x + log4(x-2)=log4(15)I know how do the example in my book but I don't know what I'm doing wrong here. log4 x +
1. 2 answers
2. asked by Anonymous
3. 1,733 views
Can someone explain how to figure out these types of problems?Solve log3 (x - 4) > 2. Evaluate log7 49. If log5 4 ≈ .8614 and
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2. asked by Nikki
3. 682 views
Which of the following options rewrites log4(9m3n) using the Quotient Rule of Logarithms, the Product Rule of Logarithms, and
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2. asked by anonymous tortel
3. 98 views
Which of the following options rewrites log4(9m3n) using the Quotient Rule of Logarithms, the Product Rule of Logarithms, and
1. 1 answer
2. asked by hi
3. 105 views
Simplify:1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4. log4^3-log4^48 I need to see all of the steps. Thanks
1. 1 answer
2. asked by Brandon
3. 747 views
Solve, round to four decimal places if necessary:log4(x-9)=2 Answer: x-9=4^2 x-9=16 x=11 log4(z)+log4(z-3)=1 Answer: z+z-3=1
1. 2 answers
2. asked by Lucy
3. 799 views
log4(2*256x^4)i know that log4(2)+log4(256)+log4(x^4) = log2^2(2)+4+4log4(x) but now I am stuck thanks
1. 1 answer
2. asked by Matilda
3. 296 views
Solve the equation algebraically. Round the result to three decimal places.log4 x - log4(x-1) = 1/2 I have no idea how to do
1. 2 answers
2. asked by Hannah
3. 977 views
Please check the following:Solve log4(m-3)+ log4(m+3) =2 Answer: 1 Solve 6^3n=43^5n-4 Answer: 1.1202 Solve 5^2x+1>=50
1. 1 answer
2. asked by Lucy
3. 1,496 views
Solve the logarithmic equation log4(6−n)=log4(3n)
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2. 25 views