Solve 6sin^2 x-5cosx-2=0 in the

Solve 6sin^2 x-5cosx-2=0 in the interval 0≤x≤2π
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2. asked by Pâro
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How do I solve these?1) 2sinxcosx-cosx=0 2) cos^2(x)-0.5cosx=0 3) 6sin^2(x)-5sinx+1=0 4) tan^2(x)+tanx-12=0
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Compute inverse functions to four significant digits.cos^2x=3-5cosx rewrite it as.. cos^2x + 5cosx -3=0 now you have a
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2. asked by Kate
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Compute inverse functions to four significant digits.cos^2x=3-5cosx cos^2x + 5cosx -3=0 now you have a quadratic, solve for cos
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2. asked by Kate
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6sin(2x)+3=0How do you find the smallest value of x in the interval 0≤x≤π for which y=0? My work so far: 6sin(2x)=-3
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2. asked by Autumn
3. 1,106 views
Solve 3sin2x - 1 = 0Interval: [0, 2 pi] Solve 6cos^2x + 5cosx - 6 = 0
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2. asked by -
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How do I take the derivative of 3(sin(x))^2 cos(x)? Are these right--> 3(sin(x))^2 *-sin(x) + cos(x)*6sin(x)*cos(x)=(-3sin(x))^3
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2. asked by Anonymous
3. 459 views
Can someone help me solve this problem:cos^2x + 5cosx - 2= 0 I don't know how to find x
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2. asked by Anonymous
3. 453 views
2(sinx)^2-5cosx-4=0Solve for all solutions between [0,2pi]
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2. asked by Anonymous
3. 803 views
Can someone help me solve this problem:cos^2x + 5cosx - 2= 0 I am having trouble finding x
1. 1 answer
2. asked by Anonymous
3. 527 views