Solve 4sin^2 x + 4sqrt(2)

Solve the equation for solutions in the interval 0<=theta<2piProblem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1
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2. asked by Renee
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So I posted these...but no one answered them. Are they right?Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x. My
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2. asked by Jason
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Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x.My answer: (pi/4)+2(pi)k, (7pi/4) + 2(pi)k Solve 2cos^2
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2. asked by Danny
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Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x.My answer: (pi/4)+2(pi)k, (7pi/4) + 2(pi)k Solve 2cos^2
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2. asked by Jason
3. 581 views
how can you find the bounderies given by the curve x=4sqrt(y) and y=4sqrt(x)? show your solution please. thanks to anyone who
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2. asked by Lucy
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Divide (4sqrt(10))/(sqrt(2)) Provide an exact answer. (1 point)2sqrt(5) 2sqrt(10) This expression is already simplified and
1. 1 answer
2. 134 views
Divide (8sqrt(6))/2 Provide an exact answer. (1 point)0 8sqrt(3) O 4sqrt(3) This expression is already simplified and cannot be
1. 1 answer
2. 126 views
If x = sqrt(5) y = 4sqrt(10) z = 3sqrt(6)(A) y = 4sqrt(2) * x (B) y < z < x C) X ^ 2 = z (D) z = (x ^ 2)/y
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6. Prove that f(x) = (3/4)x^4 + 2 and g(x) = (4sqrt(108x-216))/3 are inverses.I know you solve it with composite functions
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2. asked by Emily
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Look at the square ABCD below. A(- 2, 0) B(0, 6) C(6,4) and D(4, - 2)(1 point) 5 What is its perimeter? 8sqrt(40) 8sqrt(10)
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