Solve 2cos^2θ/2 = cos2θ for

Solve the following Trigonometric equations, where 0 <= x <= 2πa) sin^2 θ-1 = 0 b) cos2θ=1 c) 4sin^2 θ-3 = 0 d) 2cos^3 - cos
1. 1 answer
2. asked by Muneer
3. 415 views
Solve 2cos^2θ/2 = cos2θ for 0º≤θ≤360º. (Hint: Graph each side of the equation and find the points of intersection.)A)
1. 1 answer
2. asked by TeeKay
3. 788 views
cosA= 5/9 find cos1/2Aare you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
1. 0 answers
2. asked by Anonymous
3. 828 views
the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
1. 3 answers
2. asked by alex
3. 880 views
Given that 2cos^2 x - 3sin x -3 = 0, show that 2sin^2 x + 3sin x +1 = 0?Hence solve 2cos^2 x + 4sin x - 3 = 0, giving all
1. 2 answers
2. asked by Sean
3. 990 views
What am I doing wrong?Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
1. 1 answer
2. asked by Anonymous
3. 1,002 views
Solve the equation on the interval 0 less than or equals theta less than 2 pi 0≤θ<2π. 2cos^(2)\theta +\sqrt(2cos\theta
1. 1 answer
2. asked by Yana
3. 637 views
If θ represents an angle such that sin2θ = tanθ - cos2θ, then sin θ - cosθ =A. -√2 B. 0 C. 1 D. 2√2 What equation can
1. 3 answers
2. asked by Peter
3. 1,803 views
Determine the solution of the equetion: 2cos x-1=0? 2cos x=0? and 2cos x+1=0?
1. 3 answers
2. asked by Miley
3. 512 views
how does 2cos(2x)-2cos(x)sin(x) becomes 2cos(2x)-sin(2x)? Try to explain each step simply.
1. 1 answer
2. 78 views