Solve: sqrt3x+6 + 4 =<

Solve: sqrt3x+6 + 4 =< 7sqrt3x+6 + 4 =< 7 subtract 4 from both sides sqrt3x+6 =< 3 subtract 6 from both sides 3x/3x =< -3x/3x x
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2. asked by Jon
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Simplify, (2 sqrt3x^5 - 2sqrt y)^2
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2. asked by helen
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Finish the following to make a perfect square.1.) x^2+sqrt3x+______ 2.) x^2+4x+_____
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2. asked by Lily
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Finish the following to make a perfect square.1.) x^2+sqrt3x+______ 2.) x^2+4x+_____
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2. asked by Kate
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I need help solving the following problem. Could someone please help me and explain how to work the equation. Thanks in advance.
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2. asked by Jedidiah
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Convert to rectangular: theta=(2pi)/3A. y=-sqrt3 B. y=-sqrt3x C. x=sqrt3 D. x=-sqrt3y
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2. asked by Iris
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Limit x approches 1(sqrt(1+2x)-(sqrt3x))/(sqrt(3+x)-2sqrt(x))
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2. asked by Harpreet
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Find the equation of a line passing through the origin so that the tangent of the angle between the line in quadrantI and the
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2. asked by y912f
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sqrt3x^5y^14To simplify: sqrt(3 x^5 y^14) The square root of x^4 is x^2. The square root of y^14 is y^7. Can you determine what
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2. asked by Margie
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First: solve for k. Then, go back to the original equation c=k(d-3) and solve for c when d is ten.Second: Area=k*s^2 Put in the
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2. asked by SraJMcGinn
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