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Solve: sec(x)^2= 3tanx +1 ***
2sec^2x -3tanx =5 for [0,2pi)
Please solve for the values of x for me.
2 answers
asked by
tom
509 views
Solve the following equations for 0 < x < 2pi
A) sin^2x=2sinxcosx B) 3tanx=cosx Please help Thankyou
2 answers
asked by
Anonymous
673 views
solve: tanx+tan2x+√3tanx tan2x=√3 (0<=x<=360)
3 answers
asked by
rabin
4,855 views
Solve:
sec(x)^2= 3tanx +1 *** It is suppose to be the sqaure root of 3 but i could find the symbol so just wrote the 3 without it
1 answer
asked by
Jack
669 views
if f(x)=3tanx +2
2 answers
asked by
pete
327 views
Differentiate x-3+3tanx
5 answers
asked by
Sandra
106 views
2sec^2x -3tanx =5 for [0,2pi)
2 answers
asked by
tom
936 views
tan3x=(3tanx-tan^3x)/(1-3tan^2x)
1 answer
asked by
Mayna
2,712 views
2sec^2x - 3tanx - 5 = 0
over the interval 0 to 2pi x= 1.14, 4.28, 5.68, and 2.54 right?
2 answers
asked by
tom
979 views
s- integral
s 1/ [ (x^4) sq.rt(x^2+9)] i know x=3tanx sq.rt(x^2+9)= 3 secx dx= 3/[cos^2(x)] so far i know: = 1/ (3tan^4(x)) 3secx
0 answers
asked by
christine
689 views