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Solve: Log5(x-2) + log8(x-4)= log6(x-1)

  1. Solve:Log5(x-2) + log8(x-4)= log6(x-1)
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    2. NR asked by NR
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  2. Solve for x: log5(x-2)+log8(x-4) = log6(x-1). I do not have any idea on this topic.
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    2. Seth asked by Seth
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  3. Solve for the value of x: log5(x-2)+log8(x-4)=Log6(x-1)..For your information that 5,8 and 6 are bases not just multipliers.
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    2. Seth asked by Seth
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  4. Expand the expression log(8x5) using the properties of logarithms.(1 point) Responses log8+logx log8+logx log8+logx−log5
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    2. pakyo asked by pakyo
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  5. Expand the expression log(8x/5) using the properties of logarithms1)log8+logx 2)log8+logx-log5 3)8logx-log5 4)log8/log5 x
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  6. PLEASE CHECK MY ANSWERS1. Write f(x)=4^x-3 in f(x)=ab^x F(x)=(1/64)(4)^x 2.solve for x 4^x+2=3^x-5 X=-log4/3(3888) 3.solve for x
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    2. Lexy asked by Lexy
    3. views icon 478 views
  7. The problem I have to solve is log with base 2 ^6 multiply by log base 6 ^ 8.I use the change of base formula and got log6/log2
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    2. Shadow asked by Shadow
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  8. Solve for x: log5(x-2)+ log5 (x-4) = log6(x-1)
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    2. Jeconiah asked by Jeconiah
    3. views icon 762 views
  9. Expand the expression log(8x5)log ⁡ ( 8 𝑥 5 ) using the properties of logarithms.(1 point) Responses 8logx−log5 8 log ⁡
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    2. views icon 28 views
  10. log27+log8-log128 and log6-log8
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    2. Evan asked by Evan
    3. views icon 242 views