Solve: 2log_3(x) - log_3(x-2) =

Solve:2log_3(x) - log_3(x-2) = 2 My Work: log_3(x^2) - log_3(x-2) = log_3(3^2) log_3 [(x^2) / (x-2)] = log_3(27) (x^2) / (x-2) =
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Rewrite the expression log_3(z) + log_3(2) + log_3(4) as a single logarithm. (1 point)1)log_3 (8z) 2)log_3 (24z) 3) log_3 (z+6)
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Rewrite the expression log_3(z) + log_3(2) + log_3(4) as a single logarithm. (1 point)
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Rewrite the expression log_3(z) + log_3(4) + log_3(4) as a single logarithm. (1 point)
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Solve the equation:log_3(x²+x)-log_3(x²-x)=1
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log_3(2x - 1) = 2, Find x.Here's what I've done: log_3(2x) * log_3(1) = 2 log2x/log3 * log1/log3 = 2 trial and error... log2
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2. asked by Anonymous
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2log_3(9)solve
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2. asked by Hasane
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Given that x=log_3 5 and y=log_3 2, rewrite log_3 60 in terms of x and y.
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2. asked by Daniel
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Which of the following logarithmic expressions is undefined?(1 point) 1) log_0.25 (64) 2) log_3 (-9) 3) log_2.5 (6.25)
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find the zero(es) of the function f(x)=log_3(x-1)+log_3(2x+3)a. x=2 and x=-1 b. x=1 and x=-2/3 c. x=-1+ sqr 33/4 d. x=-1 +- sqr
1. 5 answers
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