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Solve: (log2 8)^x - (log9
Solve for x
1. log5 X=3 2. Log2 16-log2 =x 3. Log9 6561=x
1 answer
asked by
bobby
609 views
Solve:
(log2 8)^x - (log9 3)^x+1 = 0
7 answers
asked by
Cyn
666 views
using logarithms to solve exponential equations.
5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1
1 answer
asked by
Joe
787 views
i need help with these two homework problems
Use the Laws of Logarithms to combine the expression into a single logarithm log2 5
1 answer
asked by
Emma
832 views
using logarithms to solve exponential equations.
5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1
4 answers
asked by
Joe
677 views
log9 1= _______ (fill in the blank)
Let x=log2 1/32 . Write the exponential form of the equation and solve the equation for x.
2 answers
asked by
math help
1,190 views
solve the equation
log2(x+4)-log4x=2 the 2 and 4 are lower than the g This is what I got: log2(x+4)+log2(4^x)=2 log2((x+4)*4^x)=2
1 answer
asked by
anonymous
1,057 views
simply
log9 3 + log 9 27 and 2log7+ log2
1 answer
43 views
find the value of log9 0.24. (hint: log2=0.301 log3=0.477)
1 answer
asked by
help
408 views
Express as a logarithm of a single number or expression:
1. 5log4^p+log4^q 2. log10^x-4 log10^y 3. 4log3^A-1/2 log3^B 4.
1 answer
asked by
Brandon
954 views